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Kirchhoff's Current Law problem

  1. Aug 19, 2013 #1
    1. The problem statement, all variables and given/known data
    cSaOCJS.png


    3. The attempt at a solution

    Currents entering the top node...

    [itex]\frac{V}{6000} - 0.01 - \frac{V}{9000} - \frac{V}{8000} + 0.009 - \frac{V}{3000} = 0[/itex]

    Solve for V I get -2.48

    The current Ia is the addition of the current going out of Rd add Is2

    so... [itex]I = \frac{2.48}{3000} =0.000823 [/itex] Therefore.. [itex]I_{A} = 0.000823 - 0.009= -0.008172 [/itex] This is wrong... the answer is -9.45mA and I get -8.17mA

    Anyone care to help me out!
     
  2. jcsd
  3. Aug 19, 2013 #2

    gneill

    User Avatar

    Staff: Mentor

    Check the sign on the first term of your KCL equation...
     
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