Kirchhoff's Rules and Systems of Equations

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SUMMARY

The discussion focuses on applying Kirchhoff's Rules to solve for currents in a circuit with both series and parallel components. The circuit includes resistors R1 (97.8 ohms), R2 (325 ohms), and R3 (553 ohms), powered by a 2.62-volt battery. The user attempts to derive equations based on measured currents I1 (7.43 mA), I2 (24.3 mA), and I3 (24 mA) but encounters discrepancies in their calculations. The error identified involves incorrect manipulation of the equations, specifically in the division of terms involving R1 and R3.

PREREQUISITES
  • Understanding of Kirchhoff's Voltage Law (KVL)
  • Familiarity with Kirchhoff's Current Law (KCL)
  • Basic knowledge of series and parallel circuits
  • Proficiency in solving systems of linear equations
NEXT STEPS
  • Review Kirchhoff's Laws and their applications in circuit analysis
  • Practice solving systems of equations using substitution and elimination methods
  • Explore circuit simulation tools like LTspice or Multisim for visualizing circuit behavior
  • Investigate common mistakes in circuit analysis and how to avoid them
USEFUL FOR

Students studying electrical engineering, educators teaching circuit analysis, and hobbyists working on electronics projects who need to understand current calculations in complex circuits.

succubus
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Homework Statement


To find the current traveling through a circuit with parallel and series connections. The circuit looks something like this.

*Right now my webserver is giving me fits and won't let me login. I will try and get a picture to those who cannot understand what I am about to describe below, and with my poor description skills, will probably be everyone.

It's a series/parallel circuit. First there is R1(97.8), and then the circuit splits into parallel with R3(553) on the outside and R2(325) on the inside, and then continues around to a battery that has a measured voltage of 2.62 volts.

We measured the current in the lab, so we have the answers. The problem is, were supposed to use systems of equations to discover the answer as if we didn't measure it. IO have tried my best to do something about, and these are the equations I have come up with (we were only told to use 3, not the 4th for the inner current) and tried solving for each individual variable to no avail. This is what I've done.

Homework Equations



Outer current
(1) V-R1I1 - R3I3 = 0
Parallel Loop Current (Inside parallel circuit from R3 to R2)
(2) -R3I3 + R2I2 = 0
Junction Rule
(3) I1 = I2 +I3

I'm pretty sure my equations are correct.

I substituted I1 in equation 3 into equation 1 to get

V-R1(I2 + I3) - R3I3 = 0
Then I solved for I2
-R1I2 - R1I3 - R3I3 = -V
-R1I2 - I3(R1 + R3) = -V
-V + I3(R1 + R3) = -R1I2
(Divide by R1)

-V + I3(R3) = - I2

I2 = V - R3I3

Then I substituted what I got for I2 into equation 2

-R3I3 + R2(V-R3I3) = 0

-R3I3 - R2V - R2R3I3 = 0

-R3I3 - R2R3I3 = R2V

-I3(R3 + R2R3) = R2V
Divide by R3 + R2R3 yields

-I3 = V/2R3

which gives me something similar to the current I measured for I3, but 1 decimal off.

Measured currents are below

I1 = 7.43 mA
I2 = 24.3 mA
I3 = 24 mAWhere did I go wrong? When I plug in the answers they don't come anywhere close to what I measured across the circuit. I'm pretty sure we measured the current correctly. :/
 
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succubus said:

Homework Statement


To find the current traveling through a circuit with parallel and series connections. The circuit looks something like this.

*Right now my webserver is giving me fits and won't let me login. I will try and get a picture to those who cannot understand what I am about to describe below, and with my poor description skills, will probably be everyone.

It's a series/parallel circuit. First there is R1(97.8), and then the circuit splits into parallel with R3(553) on the outside and R2(325) on the inside, and then continues around to a battery that has a measured voltage of 2.62 volts.

We measured the current in the lab, so we have the answers. The problem is, were supposed to use systems of equations to discover the answer as if we didn't measure it. IO have tried my best to do something about, and these are the equations I have come up with (we were only told to use 3, not the 4th for the inner current) and tried solving for each individual variable to no avail. This is what I've done.

Homework Equations



Outer current
(1) V-R1I1 - R3I3 = 0
Parallel Loop Current (Inside parallel circuit from R3 to R2)
(2) -R3I3 + R2I2 = 0
Junction Rule
(3) I1 = I2 +I3

I'm pretty sure my equations are correct.

I substituted I1 in equation 3 into equation 1 to get

V-R1(I2 + I3) - R3I3 = 0
Then I solved for I2
-R1I2 - R1I3 - R3I3 = -V
-R1I2 - I3(R1 + R3) = -V
-V + I3(R1 + R3) = -R1I2
(Divide by R1)

-V + I3(R3) = - I2

I2 = V - R3I3

Then I substituted what I got for I2 into equation 2

-R3I3 + R2(V-R3I3) = 0

-R3I3 - R2V - R2R3I3 = 0

-R3I3 - R2R3I3 = R2V

-I3(R3 + R2R3) = R2V
Divide by R3 + R2R3 yields

-I3 = V/2R3

which gives me something similar to the current I measured for I3, but 1 decimal off.

Measured currents are below

I1 = 7.43 mA
I2 = 24.3 mA
I3 = 24 mA


Where did I go wrong? When I plug in the answers they don't come anywhere close to what I measured across the circuit. I'm pretty sure we measured the current correctly. :/

You went wrong here:
-V + I3(R1 + R3) = -R1I2
(Divide by R1)

-V + I3(R3) = - I2

R1 + R3 divided by R1 is not R3.
 

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