Kirchhoff's rules for resistors in parallel

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SUMMARY

This discussion focuses on applying Kirchhoff's rules to analyze a circuit with resistors in parallel. The circuit includes an electromotive force (emf) of 9 V, an internal resistance of 1.5 ohms, and three resistors: R1 at 5 ohms, R2 at 15 ohms, and R3 at 13.75 ohms. The user calculated the current I1 to be 0.9328 A by considering the total resistance and the configuration of the resistors. The discussion emphasizes the importance of visualizing current splits and suggests redrawing the circuit for clarity.

PREREQUISITES
  • Understanding of Kirchhoff's Voltage Law (KVL)
  • Familiarity with circuit analysis techniques
  • Basic knowledge of resistors in parallel
  • Ability to interpret circuit schematics
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Students in electrical engineering, circuit designers, and anyone studying circuit analysis who seeks to deepen their understanding of Kirchhoff's rules and resistor configurations.

coleman221
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Homework Statement



25tko42.jpg


Use Kirchoff's rules to determine I1, I2 and I3 for the following circuit:
Use the following values:ε = emf = 9 V
r = internal resistance = 1.5
R1 = 5
R2 = 15
R3 = 13.75

Homework Equations



The Attempt at a Solution


I found I1 to be .9328 by adding all the resistors together (taking into account that r3 was in parallel to r1 and r2) and adding the resistance of the battery.

I've been trying to use 0=ε-I1r-IR1-IR2
0=ε-I1r-I3R3
I1=I2+I3
I've done similar problems but this is for a lab instead of homework so its written in different a way (and they like to throw in things we haven't learned yet in lecture) so i think I'm having trouble visualizing where the currents are splitting and what parts are equivalent.
 
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updated to add correct image
 
Why not redraw the circuit in a more conventional way, using the standard schematic symbols? It might help you to see ways to go about analyzing it.
 

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