Kirchhoff's Rules Homework Solution

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SUMMARY

The discussion focuses on applying Kirchhoff's laws to solve a circuit problem presented in a homework assignment. The user derived five equations based on the loop rule but encountered issues when reducing the corresponding matrix to row echelon form, resulting in zero currents. Key insights indicate that the user has three loops but created five loop equations, leading to linear dependencies and an incomplete system due to the absence of junction-rule equations. The discussion emphasizes the importance of correctly labeling diagrams and ensuring all necessary equations are included.

PREREQUISITES
  • Understanding of Kirchhoff's Loop Rule and Junction Rule
  • Familiarity with matrix operations and row echelon form (REF)
  • Basic circuit analysis concepts, including current and voltage relationships
  • Ability to interpret and label circuit diagrams accurately
NEXT STEPS
  • Review Kirchhoff's Laws in detail, focusing on practical applications
  • Practice solving circuit problems using matrix methods and REF
  • Learn about the significance of junction-rule equations in circuit analysis
  • Explore circuit simulation tools to visualize and verify circuit behavior
USEFUL FOR

Electrical engineering students, circuit designers, and anyone studying circuit analysis who seeks to deepen their understanding of Kirchhoff's laws and their application in solving complex circuits.

ma18
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Homework Statement



Find Kirchoff's laws for this
http://postimg.org/image/d78dvdg5f/

(Actual problem has a bit more but I can do that part.)

Homework Equations



Loop rule
Junction rule

The Attempt at a Solution



I got the following equations

2e - 4i_4 - 2i_2 = 0
e - 3i_3 - i_1 = 0
e - 4i_4 - i_1 = 0
2e - 3i_3 - 2i_2 = 0
3e - i_1 - 2i_2 = 0

I used these in a matrix but when I reduced to rref I got zero's for the currents which doesn't make sense.

Thanks,

P.S This is from a 2nd year Uni course
 
Last edited:
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It helps to label your diagram.
You appear to have put ##e=\varepsilon/R##
I don't see where 3e comes from.

You have three loops - but 5 loop equations - this means that you will get zero lines in the matrix (some of rows are linear combinations of the others) and you appear to have no junction-rule equations: these will not have any e's in them. So your system of equations may be incomplete.
 

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