Kirchoff's circuits and the Electric Field

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SUMMARY

This discussion focuses on the relationship between electric fields and current in circuit analysis, specifically through the lens of Kirchhoff's laws. The equation $$-\varepsilon_1 + IR_1 + \varepsilon_2 + IR_2 = 0$$ is examined alongside the integral $$\int_{b}^{c} \mathbf{E}\cdot d\mathbf{s} = -\Delta V$$, highlighting the consistency between electric field direction and current flow. The conversation also addresses the applicability of these principles to circuits with inductors versus resistors, emphasizing that the integral form may not hold in non-conservative fields. The importance of understanding voltage gradients and their relation to current direction is underscored.

PREREQUISITES
  • Understanding of Kirchhoff's Circuit Laws
  • Familiarity with Electric Field concepts
  • Knowledge of Ohm's Law
  • Basic calculus for evaluating integrals
NEXT STEPS
  • Study the implications of non-conservative electric fields in circuit analysis
  • Learn about the role of inductors in AC circuits
  • Explore advanced applications of Kirchhoff's laws in complex circuits
  • Investigate the relationship between electric potential and electric field in various circuit configurations
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Physics students, electrical engineers, and anyone interested in deepening their understanding of circuit theory and the interplay between electric fields and current flow.

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Homework Statement



circuitlry.jpg


I have drawn the direction of the electric field in the picture.

I saw this on a video on youtube where this guy solves circuit problems solely on looking at the direction of the electric field. Basically he follows the current and the electric field

$$-\varepsilon_1 + IR_1 + \varepsilon_2 + IR_2 = 0$$

What is the different theory behind the approach? Is it a coincidence that they both will give the same answer or is one of them wrong? For instance between $$b$$ and $$c$$, the electric field and the current is in the same direction so we have

$$\int_{b}^{c} \mathbf{E}\cdot d\mathbf{s} =\int_{b}^{c} Eds = -\Delta V$$


Which means the potential should be minus, but "according to Ohm's Law, the electric field and the current are in the same direction, so we get +IR" and in the battery we go "against the electric field, so we get $$-\varepsilon$$.


The circuit the guy on youtube () does involves an inductor, but I thought I could apply the same principle to regular resistor circuits. Does the equation $$\int_{b}^{c} \mathbf{E}\cdot d\mathbf{s} = -\Delta V$$ no longer hold? Note that the integral isn't a closed loop.

Thank you for reading
 
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In your Kirchoff's analysis, you are using symbol E for the voltage across each component, so E has units of volts. Once you mark in a loop's current arrow, you can determine the voltage E across each component because to cause current to flow in a resistor in the agreed direction, one particular end of that component must be positive relative to the other.

In ∫E.ds the term E is the voltage gradient, in volts/metre. You don't know E in the circuit, nor s, so this equation is of no use here.
 

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