Kirchoffs Law and simple circuit problem

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QuarkCharmer
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Homework Statement


The problem is in the attached image. I can't figure out what is going on. The circuit as given is at the top, I have circled what I am trying to find.

Homework Equations



The Attempt at a Solution


I used the junction law to find the current through the 3 ohm resistor to be 8 amps. Then I took three loops of the system and applied kirchhoffs voltage law, and solved the system of three equations and 3 unknowns, but it's inconsistent. I don't see where I am going wrong but I suspect it has something to do with my loops.

2ptdsb8.jpg


No matter how I do this, it always works out to be impossible?

Thanks
 
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I think you're overthinking this :smile:

Assign a potential of 0V to the node labeled d (make it a reference node). Then using the known currents and resistances, assign relative potentials to nodes b, h, f. Continue...
 
That potential of 0 volts is from which voltage source though? I'm not sure I understand what you mean exactly. I have done about 20 problems like this, finding currents and resistances and emf's without any problems just doing loops and solving. It should work?

If you mean, using node d as the "ground" if I were say, hooking up a multimeter or something, then how do you know that node d has 0 potential?
 
QuarkCharmer said:
That potential of 0 volts is from which voltage source though? I'm not sure I understand what you mean exactly. I have done about 20 problems like this, finding currents and resistances and emf's without any problems just doing loops and solving. It should work?

If you mean, using node d as the "ground" if I were say, hooking up a multimeter or something, then how do you know that node d has 0 potential?

It's zero because you say it is :smile: It's a point of reference, as you say, as if you were to connect the negative lead of your multimeter to it. The same thing is done when you choose a reference node for nodal analysis. The circuit as a whole has no absolute potential reference to anything external, so you're free to assign your own "zero" reference point.

EDIT: Note that your choice of loops did not include the 3 Ω resistor in any path. That's why the system of equations you wrote would not yield a consistent result. Your equations must cover every component.
 
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I didn't know that you had to hit every component, but that makes sense since most/all of the variables are dependent on the others. To be clear, I need to make sure I cover all the components in my system, but that does not mean I need to do all possible loops right?
(I got the right solution now, knowing that information, thanks!)
 
QuarkCharmer said:
I didn't know that you had to hit every component, but that makes sense since most/all of the variables are dependent on the others. To be clear, I need to make sure I cover all the components in my system, but that does not mean I need to do all possible loops right?
Correct.
 
Got it, thanks Gneill.