- #1

urduworld

- 26

- 0

according to circuit

In Left Loop Current is I

_{1}and Right Loop is I

_{2}

Now Loop Left

10-8I

_{1}-3I

_{1}-I

_{2}=0

which becomes

10-8I1-3I1+3I

_{2}=0

11I

_{1}-3I

_{2}-10=0 ------------eq 1

Now Loop Right

15-6I

_{2}-3I

_{2}-I

_{1}=0

15-6I

_{2}-3I

_{2}+3I

_{1}=0

3I

_{1}-9I

_{2}+15=0

I1-3I

_{2}+5=0 ---------------eq 2

Deduct eq 2 from eq 1

10I

_{1}-15=0

I

_{1}= 1.5

from eq 2 we have

I

_{2}=2.1666

Now I want to ask

I= I

_{1}-I

_{2}

or

I=I

_{2}-I

_{1}

or what and how to take decision what i have to do