Kirchoff's Loop Rule as applied to Capacitors?

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Kirchhoff's Loop Rule applies to capacitors by measuring potential differences in circuits that include resistors and capacitors. The voltage across a capacitor is defined by the equation v=q/C, and in calculus-based contexts, it relates current and voltage change over time. When analyzing RC circuits, the loop rule is essential for determining current flow, especially in steady-state conditions where the capacitor is fully charged. Current through a capacitor is zero only when the charge is constant, which occurs after a long time or when the circuit reaches equilibrium. Understanding these principles is crucial for solving problems involving capacitors in electrical circuits.
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Homework Statement



How does the loop rule apply to capacitors? I can't find any examples of circuits containing capacitors and resistors where the loop rule is used. I know the loop rule measures potential differences, but I'm not quite sure if that has anything to do with capacitors? All the examples are 0 = V - IR - IR, etc.


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The Attempt at a Solution

 
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Yes, the loop rule is used with capacitors all the time. The element law for a capacitor is v=q/C. In more advanced (calculus-based) courses this is written i=C\frac{dv}{dt}. Solving this for the voltage, one obtains:

v=\frac{1}{C}\int_{t_0}^ti(\tau)d\tau+v(t_0)
 
all the basics of RC circuits (RL and RLC circuits too) come from a basic application of Kirchoff's Loop principle.
 
So when finding currents, the branch that a capacitor is on (in terms of current) is 0, right? since when a capacitor is full, no current flows.
 
not necessarily. it depends on the situation. Since charging rate = current, current=0 if and only if the charge of the capacitor is constant. This happens when the capacitor has been (dis)charging for a long time, or when the circuit reaches steady state.
 
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the problem says that the currents reach equilibrium. isn't that steady state?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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