Klein Gordon equation, probability density

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 4K views
opous
Messages
16
Reaction score
0
[SOLVED] Klein Gordon equation, probability density

Homework Statement



Use the Klein-Gordon Equation to show that

[tex]\partial_{\mu}j^{\mu} = 0[/tex]

Homework Equations



KG:

[tex]\left(\frac{\partial^{2}}{\partial t^{2}} - \nabla^{2} + m^{2}\right) \phi = (\partial_{\mu}\partial^{\mu} + m^{2}) \phi = 0[/tex]

j:

[tex]j^{\mu} = \frac{i}{2m} \left[\phi^{*}(\partial^{\mu} \phi) - (\partial^{\mu} \phi^{*}) \phi]\right[/tex]

The Attempt at a Solution



OK, so I've expanded j out, taking the differentials and have the following for my components:

time component:

[tex]\frac{i}{2m} \left[\phi^{*} \frac{\partial^{2} \phi}{\partial t^{2}} - \phi \frac{\partial^{2} \phi^{*}}{\partial t^{2}}\right][/tex]

space components:

[tex]\frac{i}{2m} \left[- \phi^{*} \frac{\partial^{2} \phi}{\partial r^{2}} + \phi \frac{\partial^{2} \phi^{*}}{\partial r^{2}}\right][/tex]

(where I've used r = (x,y,z) )

Putting them in this form:

[tex]\frac{i \phi^{*}}{2m} \left[\frac{\partial^{2} \phi}{\partial t^{2}} - \frac{\partial^{2} \phi}{\partial r^{2}}\right] - \frac{i \phi}{2m} \left[\frac{\partial^{2} \phi^{*}}{\partial t^{2}} - \frac{\partial^{2} \phi^{*}}{\partial r^{2}}\right][/tex]

Which looks slightly more like the KG equation. However, my trouble is with the mass terms, I have no (mass)² terms to complete the KG equation and hence show the desired expression is zero. Can anyone see what I'm missing here?
 
Physics news on Phys.org
Don't expand out components, just compute [tex]\partial_{\mu}j^{\mu}[/tex] expanding the partial using the product rule. You can reduce parts using the Klein-Gordon equation and then they and the other parts will cancel.