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I Ladder operators in electron field and electron's charge

  1. Jan 8, 2017 #1
    S. Weinberg says in his book, "The Quantum Theory of Fields Volume I", that

    Since electrons carry a charge, we would not like to mix annihilation and creation operators, so we might try to write the field as $$\psi(x)=\sum_{k}u_k (x)e^{-i\omega_k t}a_k$$
    where ##u_k (x)e^{-i\omega_k t}## are a complete set of orthonormal plane-wave solutions of the Dirac equation with ##k## labelling the 3-momentum, spin, and sign of the energy.
    ------
    At the first time, I thought it's because ##\sum_{k}## already involves the negative ##\omega_k## so that ##b_k## and ##b^\dagger _k## in ##\psi(x)=\sum_{k}u_k (x)e^{-i\omega_k t}b_k+u_k (x)e^{i\omega_k t}b^\dagger _k## can be merged into ##a_k##.

    But he says it's because of the electron's charge and explains no more. Can someone explain, please?

    Thank you.
     
    Last edited: Jan 8, 2017
  2. jcsd
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