Lagrangian/Stationary-action principle

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The discussion focuses on the application of the Lagrangian/Stationary-action principle to solve differential equations using the Hamiltonian function, specifically ##H(x,\dot{x},t) = -x\dot{x}^2##. The user successfully derived the function ##x(t) = \sqrt[3]{\frac{9}{4}(a-\sqrt{c}*t)^2}## and attempted to find stationary solutions by setting the first derivative of ##x(t)## to zero. However, they encountered difficulties in calculating the action functional ##S[x]= \int_{t_i}^{t_f} L(x,\dot{x})dt## and integrating terms involving ##x\dot{x}^2##, indicating a need for further clarification on the Euler-Lagrange equations.

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Lambda96
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Homework Statement
Find a stationary solution
Relevant Equations
Lagrangian ##L=x\dot{x}(2\alpha - \dot{x})##
Hi

the text is unfortunately a bit longer, but I have included it anyway to provide all the information.

Bildschirmfoto 2022-11-29 um 19.17.39.png

I am not sure if I understood the task b correctly, but I understood it as follows: using the equation ##H(x,\dot{x},t)##, solve the differential equation for ##x(t)##.

Once you have found ##x(t)##, you have to use it to find the statin solutions, i.e. form the first derivative of ##x(t)## and set it to 0.

I then first formed ##H(x,\dot{x},t)## and got the following ##H(x,\dot{x},t)=-x\dot{x}^2##

And ##H(x,\dot{x},t)=c## which leads to ##c=-x\dot{x}^2##

After that, I did the separation of variables,

$$\sqrt{x}dx=-\sqrt{c}dt$$

Then I integrated both sides and solved for ##x(t)## and got the following.

$$x(t)=\sqrt[3]{\frac{9}{4}(a-\sqrt{c}*t)^2}$$

##a## is the constant of integration.

Now, to get the stationary solution, I have to form ##\frac{dx(t)}{dt}=0##.

Have I done everything right up to this point, or have I completely misunderstood the task?
 
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I guess they meant to find the solution of the Euler-Lagrange equations, which makes the "action functional" stationary. I've not checked your calculation in detail, but it looks reasonable.
 
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Thank you vanhees71 for your help

I then determined the following form with the help of the initial condition ##x(t_i)=0##.

$$x(t)=\frac{9c}{4}^{1/3}(t_i-t)^{1/3}$$

In task c you had to derive the Euler Lagrange equation and put ##x(t)## in there, and with the above result I get 0.

Unfortunately, I can't get any further with task d.

Bildschirmfoto 2022-11-30 um 20.01.15.png

I would have simply calculated the above functional with ##S[x]= \int_{t_i}^{t_f} L(x,\dot{x})dt ## with ##x(t)##, ##\dot{x}(t)## which I got in task b but Q does not appear at all when I solve the integral?
 
I don't understand (d).

Note that the piece
$$\tilde{L}=2 \alpha x \dot{x}=\frac{\mathrm{d}}{\mathrm{d} t} (\alpha x^2).$$
Check, what this term contributes to the equations of motion!
 
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Thank you vanhees71 for your help 👍

I had already thought of that, that I form the antiderivatives of ##S=2x\dot{x}\alpha-x\dot{x}^2## and just put ##x(t)## there, unfortunately the expression ##x\dot{x}^2## gives me problems, because I can't find the antiderivatives for this expression, even with wolframalpha I can't find any.
 
I wanted to hint you at something else. Think about a Lagrangian of the form
$$L=\frac{\mathrm{d}}{\mathrm{d} t} f(x,t)=\dot{x} \partial_x f(x,t) + \partial_t f(x,t).$$
What are the Euler-Lagrange equations for such a Lagrangian?
 
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