Lambda decay, momentum of the pion and proton

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The discussion revolves around calculating the momentum of decay products from a lambda particle decaying into a pion and a proton, with the lambda initially moving at 0.9c. Participants emphasize the importance of using conservation of momentum and energy principles, suggesting computations should first be performed in the lambda's rest frame for clarity. Confusion arises regarding the interpretation of two potential momentum solutions, which are both considered valid due to the isotropic nature of the decay. The concept of "beaming" is introduced, indicating that decay products are preferentially emitted in the forward direction, leading to a distribution of momenta based on decay angles. Ultimately, understanding the underlying mathematics is deemed crucial for accurately plotting momentum and energy distributions in simulations.
  • #31
Orodruin said:
You should be able to deduce this from 4-momentum conservation.
I think I understand the concept of 4 momentum, but I am unsure about if I will have to be using sin/cos or some type of geometry to find the angles. I understand the conservation of momentum so then, only the x component will change and it will be the cos of the angle ?

But my problem is there are two particles decaying, the pion and the proton so they would potentially both have different angles & momentum except I only focus on the pion right now
 
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  • #32
Cocoleia said:
I think I understand the concept of 4 momentum, but I am unsure about if I will have to be using sin/cos or some type of geometry to find the angles. I understand the conservation of momentum so then, only the x component will change and it will be the cos of the angle ?
4-momentum conservation is just energy and momentum conservation wrapped up into one and a more convenient way of constructing invariant quantities.

I suggest you write down the general momentum and energy conservation equations assuming that the pion has some unknown total momentum at some angle ##\theta## to the initial direction.
 
  • #33
Orodruin said:
4-momentum conservation is just energy and momentum conservation wrapped up into one and a more convenient way of constructing invariant quantities.

I suggest you write down the general momentum and energy conservation equations assuming that the pion has some unknown total momentum at some angle ##\theta## to the initial direction.
In this case I would assume the the energy conservation is simply Ea=Eb+Ec

However for momentum if I separate into the three components,
upload_2018-5-30_9-20-0.png

but then I am ignoring the proton and if I add in that
Pa=Pb+Pc I'm not sure how to combine the angle to this
 

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  • #34
Orodruin said:
4-momentum conservation is just energy and momentum conservation wrapped up into one and a more convenient way of constructing invariant quantities.

I suggest you write down the general momentum and energy conservation equations assuming that the pion has some unknown total momentum at some angle ##\theta## to the initial direction.
Alternatively
upload_2018-5-30_9-43-44.png

upload_2018-5-30_9-44-33.png

http://www.dzre.com/alex/P442/lectures/lec_04.pdf

I see all their formulas for angles and such but I just can't relate it my head
 

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