Lambda decay, momentum of the pion and proton

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Homework Help Overview

The discussion revolves around a lambda particle decaying into a pion and a proton, with the lambda initially moving at a velocity of 0.9c. Participants are exploring the momentum of the decay products and the implications of conservation laws in this context.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the ambiguity of having two solutions for momentum and question the physical significance of each. There is a focus on understanding the decay in both the moving and rest frames of the lambda particle. Some participants suggest performing calculations in the lambda's rest frame to clarify the situation.

Discussion Status

The discussion is active, with participants providing guidance on how to approach the problem, particularly regarding the interpretation of momentum in different frames. There is an acknowledgment of the complexity of the decay process and the potential for multiple outcomes based on the decay angle.

Contextual Notes

Participants note the challenge of understanding the implications of momentum conservation and the nature of decay products in a relativistic context. There is mention of the need to consider isotropic decay and the concept of beaming in the analysis.

  • #31
Orodruin said:
You should be able to deduce this from 4-momentum conservation.
I think I understand the concept of 4 momentum, but I am unsure about if I will have to be using sin/cos or some type of geometry to find the angles. I understand the conservation of momentum so then, only the x component will change and it will be the cos of the angle ?

But my problem is there are two particles decaying, the pion and the proton so they would potentially both have different angles & momentum except I only focus on the pion right now
 
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  • #32
Cocoleia said:
I think I understand the concept of 4 momentum, but I am unsure about if I will have to be using sin/cos or some type of geometry to find the angles. I understand the conservation of momentum so then, only the x component will change and it will be the cos of the angle ?
4-momentum conservation is just energy and momentum conservation wrapped up into one and a more convenient way of constructing invariant quantities.

I suggest you write down the general momentum and energy conservation equations assuming that the pion has some unknown total momentum at some angle ##\theta## to the initial direction.
 
  • #33
Orodruin said:
4-momentum conservation is just energy and momentum conservation wrapped up into one and a more convenient way of constructing invariant quantities.

I suggest you write down the general momentum and energy conservation equations assuming that the pion has some unknown total momentum at some angle ##\theta## to the initial direction.
In this case I would assume the the energy conservation is simply Ea=Eb+Ec

However for momentum if I separate into the three components,
upload_2018-5-30_9-20-0.png

but then I am ignoring the proton and if I add in that
Pa=Pb+Pc I'm not sure how to combine the angle to this
 

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  • #34
Orodruin said:
4-momentum conservation is just energy and momentum conservation wrapped up into one and a more convenient way of constructing invariant quantities.

I suggest you write down the general momentum and energy conservation equations assuming that the pion has some unknown total momentum at some angle ##\theta## to the initial direction.
Alternatively
upload_2018-5-30_9-43-44.png

upload_2018-5-30_9-44-33.png

http://www.dzre.com/alex/P442/lectures/lec_04.pdf

I see all their formulas for angles and such but I just can't relate it my head
 

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Last edited:

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