Lande' g-Factor: Is a Reduced Mass Correction Needed?

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SUMMARY

The discussion centers on the Lande' g-factor and the potential need for a reduced mass correction. The formula presented is g = g_L (J(J+1)-S(S+1)+L(L+1))/(2J(J+1)) + g_s(J(J+1)+S(S+1)-L(L+1))/(2J(J+1)). While g_L is commonly accepted as 1, Bethe and Salpeter suggest a correction of g_L = 1 - (m_e/m_i). The participants agree that g_s does not require a reduced mass correction, as it pertains solely to the electron. The conversation highlights the nuanced contributions of angular momentum from both the electron and the nucleus.

PREREQUISITES
  • Understanding of quantum mechanics principles
  • Familiarity with the Lande' g-factor
  • Knowledge of angular momentum in atomic systems
  • Basic concepts of reduced mass in physics
NEXT STEPS
  • Research the implications of reduced mass corrections in quantum mechanics
  • Study the derivation of the Lande' g-factor in detail
  • Examine the role of nuclear magnetic moments in atomic physics
  • Explore the differences between g_L and g_s in various atomic systems
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Physicists, students of quantum mechanics, and researchers interested in atomic structure and magnetic properties will benefit from this discussion.

Khashishi
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Ok. The Lande' g-factor is given as
g = g_L \frac{J(J+1)-S(S+1)+L(L+1)}{2J(J+1)} + g_s\frac{J(J+1)+S(S+1)-L(L+1)}{2J(J+1)}

Most sources say that g_L = 1 exactly, but Bethe and Salpeter p214 seems to indicate that there should be a correction for reduced mass. g_L = 1- \frac{m_e}{m_i}

Is that right? I think so, but I wanted to make sure, since nowhere else do I see it.

I assume g_s doesn't need any correction for reduced mass, since it's just the electron acting alone. Is that right?
 
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I haven't seen it outside that book or the article by Lamb they cite, but then again, it does seem like the kind of detail any book except for Bethe & Salpeter would hide under the rug. Except for the case of Hydrogen and possibly Helium, it really is a small effect.

Did you read the following paragraph, by the way? There is a reasonable argument to why that effective gL factor should appear. Basically, some of the angular momentum of the atom is contributed by the nucleus, so if we separate the two contributions we get this term and one from the nucleus, which is negligible. And yeah, the gS must be a different matter, as it couples the electron's magnetic moment to a magnetic field. The nucleus could have a magnetic moment of its own though, something Bethe and Salpeter do treat in the next section.
 
Khashishi said:
Is that right? I think so, but I wanted to make sure, since nowhere else do I see it.
It sounds highly plausible. Why don't you try to proove it yourself?
 

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