Laplace transform - Dirac delta

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SUMMARY

The Laplace transform of the function te-tδ(t) can be determined using the properties of the Dirac delta function. While the Laplace transform of te-t is known to be 1/(s+1)2, the presence of the delta function modifies the integral expression significantly. Specifically, the integral involving the Dirac delta function evaluates to zero, confirming that the Laplace transform of te-tδ(t) is indeed zero.

PREREQUISITES
  • Understanding of Laplace transforms
  • Familiarity with the Dirac delta function
  • Knowledge of integral calculus
  • Basic concepts of time-domain and frequency-domain analysis
NEXT STEPS
  • Study the properties of the Dirac delta function in Laplace transforms
  • Explore integral expressions for Laplace transforms
  • Learn about the implications of delta functions in signal processing
  • Investigate advanced Laplace transform techniques for complex functions
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Students and professionals in mathematics, engineering, and physics who are working with Laplace transforms and signal analysis will benefit from this discussion.

magnifik
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i need help trying to find the laplace transform of te-t\delta(t)

i know the laplace transform of te-t is 1/(s+1)2 but i don't know how to find the laplace transform of a product with the Dirac delta
 
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You should actually set up the integral expression for the Laplace transform and use the properties of the delta function. It looks like it gives zero, but you should check it out.
 

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