Laplace transform of a piecewise function

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The discussion focuses on finding the Laplace transform of a piecewise function defined as f(t) = e^t for 0≤t<1 and 0 for t≥1. Participants clarify the correct setup for the integral, emphasizing the need to split the integral at the piecewise boundary. The integral from 1 to infinity evaluates to zero due to the function being zero in that interval. There is a correction regarding the integrand, with participants discussing the proper handling of exponential terms. The conversation highlights the importance of careful reading and comprehension in solving mathematical problems.
Feodalherren
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Homework Statement



f(t) = e^t when 0≤t<1
and 0 when t≥1

Homework Equations


Laplace transformations

The Attempt at a Solution



so the Laplace integral becomesfrom 0 to 1 ∫e^(st^2)dt + 0

how do I integrate this?
 
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Clarification:

Laplace transform or Lagrange Transform...?
 
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My bad, Laplace :).
 
Alright, let's do this:

From 0 to 1 we have one function, and from 1 onward we have another. Split up our integral as so:

$$\int_0^1 e^{-st} e^{t}dt + \int_{1}^{\infty} e^{-st}(0)dt \implies \int_0^1 e^{t(1-s)}dt$$
 
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Wait a second, doesn't the part that goes from 1 to +infinity get canceled out because the integral becomes

∫ e^(-st) (0) dt = 0

?
 
Feodalherren said:
Wait a second, doesn't the part that goes from 1 to +infinity get canceled out because the integral becomes

∫ e^(-st) (0) dt = 0

?

Excuse my reading comprehension, I thought it said f(t) = 1. Corrected.
 
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Ah now I see what I did wrong! DUH! Such a stupid mistake.

Thank you sir!
 
Feodalherren said:

Homework Statement



f(t) = e^t when 0≤t<1
and 0 when t≥1

Homework Equations


Laplace transformations

The Attempt at a Solution



so the Laplace integral becomesfrom 0 to 1 ∫e^(st^2)dt + 0

how do I integrate this?
How did you get an integrand of est2 ?

Remember, ex ⋅ ey = e(x + y), not exy :wink:
 
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I was just asking myself the same thing. I think I need to take a break. I've been doing math since 7.30 this morning. It's 1.30 pm now :).
 

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