Laplace Transform of Delta Function

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SUMMARY

The Laplace transform of the delta function evaluated at a specific point, L{δ(t-∏)tan(t)}, results in zero. The calculation involves integrating the product of the delta function and the tangent function, which simplifies to tan(∏) multiplied by e^(-∏s). Since tan(∏) equals zero, the final result confirms that the Laplace transform is indeed zero. The omission of the e^(-st) factor in the initial definition was noted but does not affect the outcome.

PREREQUISITES
  • Understanding of Laplace transforms and their properties
  • Familiarity with the delta function and its applications
  • Knowledge of the tangent function and its behavior at specific points
  • Basic calculus skills for evaluating integrals
NEXT STEPS
  • Study the properties of the delta function in Laplace transforms
  • Learn about the implications of Laplace transforms in control theory
  • Explore the use of the Laplace transform in solving differential equations
  • Investigate the behavior of trigonometric functions within Laplace transforms
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Students and professionals in mathematics, engineering, and physics who are working with Laplace transforms, particularly those focusing on signal processing and system analysis.

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Homework Statement


Evaluate the Laplace transform: L{δ(t-∏)tan(t)}


Homework Equations





The Attempt at a Solution


L{δ(t-∏)tan(t)} = ∫ δ(t-∏)tan(t) dt evaluated from 0 to ∞
=tan(∏)e-∏*s
= 0

Could someone check my work on this one? I'm suspicious that my transform is just zero. Thanks!
 
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You omitted the e^(-st) factor in the definition of the Laplace transform, but sure, 0 is correct.
 
Oops-Typing error. Thanks! :)
 

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