Laplace Transform of t*u(t-1): Get Help Now!

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SUMMARY

The Laplace transform of the function t*u(t-1) is evaluated using the definition of the Laplace transform, resulting in the expression (e^-s)(s+1)/s^2. The initial assumption that the transform is (1/s^2)(e^-s) is incorrect because t*u(t-1) is not a function of (t-1). The correct approach involves changing the limits of integration to account for the unit step function u(t-1), leading to the integral from 1 to infinity.

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Homework Statement



Find the laplace transform of;

t*u(t-1)

I always thought that the laplace transform of the function was;

(1/s^2) * (e^-s)

However, recently I was told that I was wrong!

I was told that I was wrong, because t*u(t-1) is not a function of (t-1). That in order to take the proper laplace transform of it, I needed it to turn it into a function of (t-1).

How can I do that? Can anyone help me find the proper laplace transform of my function, please?
 
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okay, this isn't too hard, let's start out with the definition of the laplace transform:

[tex]\int_0^\infty t u(t-1) e^{-st} dt= \int_1^\infty t e^{-st} dt[/tex]

and then you just need to evaluate the integral, which will give you something like:
[tex]\frac{e^{-s}(s+1)}{s^2}[/tex]
 
Thank you, I did everything and got the same result. :]
 

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