- #1

NewtonianAlch

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## Homework Statement

Could someone please explain this to me? I have read several notes on it, but do not really follow the reasoning:

## The Attempt at a Solution

When t = 0, -1/s*e^-st = -1/s because e^0 = 1.

When t goes to infinity is the part I do not fully understand.

Why did they take the absolute value? I'm guessing e^-jst goes to 1 because it's bounded between the - 1 and + 1 range but how did they determine a value of one when cos and sin will always be oscillating?