- #1

- 565

- 2

y''(t)-y(t)=0 with initial conditions y(0)=1 and y'(0)=3

My attempt:

Ly''(t)=(s^2)F(s)-s(1)-(3)

Ly'(t)=sF(s)-1

so (s^2)F(s)-s(1)-(3)-sF(s)-1=0

I need to isolate F(s) so

F(s)=-(2/s^2)

Is this correct?

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- Thread starter Ry122
- Start date

- #1

- 565

- 2

y''(t)-y(t)=0 with initial conditions y(0)=1 and y'(0)=3

My attempt:

Ly''(t)=(s^2)F(s)-s(1)-(3)

Ly'(t)=sF(s)-1

so (s^2)F(s)-s(1)-(3)-sF(s)-1=0

I need to isolate F(s) so

F(s)=-(2/s^2)

Is this correct?

- #2

Homework Helper

- 1,495

- 5

[tex]s^2 F(s)-s-3-(s F(s)-1)=s^2 F(s)-s-3-sF(s) \textcolor{red}{+} 1=0[/tex].

I am not sure how you isolated the F(s), something seems to have gone wrong there as well. You can write it like,

[tex](s^2-s)F(s)-(s+2)=0[/tex]

- #3

Science Advisor

Homework Helper

- 43,008

- 974

You wrote the problem as y"- y= 0, but you solved y"- y'= 0.

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