LaPlacian joint probability density function.

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SUMMARY

The joint probability density function (pdf) is defined as pxy(x,y)=(1/4)^2 exp[-1/2 (|x| + |y|)] for x and y spanning from negative to positive infinity. The task is to find the joint pdf for W=XY and Z=Y/X. While some participants questioned the applicability of the Jacobian due to the absolute value in the pdf, it is confirmed that the Jacobian can be used if the variables do not cross zero. The main challenge lies in transforming the limits for the new functions accurately.

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  • Understanding of joint probability density functions
  • Familiarity with the Jacobian transformation technique
  • Knowledge of integration techniques for absolute values
  • Basic concepts of multivariable calculus
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  • Study the application of the Jacobian in transformations involving absolute values
  • Research methods for determining limits of integration in multivariable calculus
  • Explore properties of joint distributions and their transformations
  • Learn about the implications of variable boundaries in probability density functions
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Mathematicians, statisticians, and students studying probability theory, particularly those working with joint distributions and transformations in multivariable calculus.

marina87
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A joint pdf is given as pxy(x,y)=(1/4)^2 exp[-1/2 (|x| + |y|)] for x and y between minus and plus infinity.

Find the joint pdf W=XY and Z=Y/X.

f(w,z)=∫∫f(x,y)=∫∫(1/4)^2*e^(-(|x|+|y|)/2)dxdy -∞<x,y<∞
Someone told me I can not use Jacobian because of the absolute value. Is that true?
So far this is what I have but I feel like I am not going anywhere.

f(w,z)=(1/4)^2∫∫e^(-(|x|+|y|)/2)dxdy
=(1/4)^2∫∫[e^-|x|/2]*e^-|y|/2]
=(1/4)^2∫[e^-|x|/2]∫e^-|y|/2]

=(1/4)^2[∫[e^(-x/2)+∫e^(x/2))] * [∫[e^(-y/2)+∫e^(y/2))] the limits from -∞<x,y<0 and 0<x,y<∞

=[(1/4)^2 ]*4*[ ∫ [e^(x/2)dx] + ∫ [e^(y/2)dy] ] 0<x,y<∞
I have problems with transforming the limits for the new functions.
 
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marina87 said:
A joint pdf is given as pxy(x,y)=(1/4)^2 exp[-1/2 (|x| + |y|)] for x and y between minus and plus infinity.

Find the joint pdf W=XY and Z=Y/X.

f(w,z)=∫∫f(x,y)=∫∫(1/4)^2*e^(-(|x|+|y|)/2)dxdy -∞<x,y<∞
Someone told me I can not use Jacobian because of the absolute value. Is that true?
So far this is what I have but I feel like I am not going anywhere.

f(w,z)=(1/4)^2∫∫e^(-(|x|+|y|)/2)dxdy
=(1/4)^2∫∫[e^-|x|/2]*e^-|y|/2]
=(1/4)^2∫[e^-|x|/2]∫e^-|y|/2]

=(1/4)^2[∫[e^(-x/2)+∫e^(x/2))] * [∫[e^(-y/2)+∫e^(y/2))] the limits from -∞<x,y<0 and 0<x,y<∞

=[(1/4)^2 ]*4*[ ∫ [e^(x/2)dx] + ∫ [e^(y/2)dy] ] 0<x,y<∞



I have problems with transforming the limits for the new functions.

Of course you can use the Jacobian, but you need to be careful to ensure that the variables therein do not cross zero; that is, |x| is perfectly well differentiable as long as x > 0 or x < 0. So, for positive w and z, what is the WY-region of {w < W < w+dw, z < Z < z+dz}? You ought to be able to find it as the union of two disjoint subregions, and in each subregion you can certainly use a Jacobian.

Now you need to look at the other cases where w> 0 and z > 0 do not both hold.
 
That is the part where I got stuck.
What is the best way to solve this problem? should I use Jacobian or should I use the distribution properties?

But my biggest question and where I need help is with the boundaries.
 

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