Largest and smallest values of marginal cost

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Homework Help Overview

The problem involves determining the largest and smallest values of the marginal cost derived from a given total cost function for a commodity. The total cost function is a polynomial expression in terms of the number of units produced, and the focus is on the behavior of its derivative within a specified range.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss finding the derivative of the cost function to identify critical points for maximizing or minimizing the marginal cost. There is some confusion regarding the interpretation of the problem and the correct application of calculus techniques.

Discussion Status

Some participants have attempted to find critical values by setting the derivative equal to zero, while others express uncertainty about the problem's requirements. There is an indication that further clarification on the approach to finding maximum and minimum values of the marginal cost is needed.

Contextual Notes

Participants note that the critical values found must be within the range of 0 to 18, and there is a hint provided in the original post that emphasizes the need to focus on the derivative of the cost function rather than the cost function itself.

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Homework Statement



Suppose the total cost of producing x units of a certain commodity is

C(x)= (1/4*x^4) + (-37/3*x^3) + (280/2*x^2) + (1200x) + (100)

Determine the largest and the smallest values of the MARGINAL cost C'(x) for 0<x<18

The largest value of the marginal cost is _____.
The smallest value of the marginal cost is _____.

Hint. The function f(x) that you have to MIN/MAX is the derivative of cost, i.e. f(x)=C'(x)

Homework Equations


I found the derivative, which is
(x^3) - (37*x^2) + (280x) +(1200)


The Attempt at a Solution



So I found the derivative which is above and found the critical values which are x=3, x=-20, but the values must be between 0 and 18? I am not really understanding this question. please help!
 
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is this an economics problem?

anyways to find the max or minimum (don't remember which one) set the derivative of the function equal to zero and then solve for the variable
 
sprint said:
is this an economics problem?

anyways to find the max or minimum (don't remember which one) set the derivative of the function equal to zero and then solve for the variable

yes, I did that and I got -3 and 20. I plugged those in back into the original equation (cost function) but the answers are incorrect.
 
enchilosa said:

Homework Statement



Suppose the total cost of producing x units of a certain commodity is

C(x)= (1/4*x^4) + (-37/3*x^3) + (280/2*x^2) + (1200x) + (100)

Determine the largest and the smallest values of the MARGINAL cost C'(x) for 0<x<18

The largest value of the marginal cost is _____.
The smallest value of the marginal cost is _____.

Hint. The function f(x) that you have to MIN/MAX is the derivative of cost, i.e. f(x)=C'(x)

Homework Equations


I found the derivative, which is
(x^3) - (37*x^2) + (280x) +(1200)


The Attempt at a Solution



So I found the derivative which is above and found the critical values which are x=3, x=-20, but the values must be between 0 and 18? I am not really understanding this question. please help!
Read that hint very, very carefully! In order to find max and min of MARGINAL cost, you want to find max and min of C', not C. Your derivative is f= C'= x^3- 37x^2+ 280x+ 1200 and you want to find the max and min of that so you must differentiate again and set that to 0!
 

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