Lasers- the avg power of the resulting laser pulse over a time interval

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SUMMARY

The discussion centers on calculating the average power of a ruby laser pulse when total population inversion is achieved. Given that half of the electrons in the excited state E2 drop to the ground state E1 in 30 nanoseconds, and considering the ruby crystal's dimensions (5.00 cm long and 1.19 cm in diameter) and the energy difference (E2 - E1 = 1.786 eV), the average power can be determined using the number of chromium atoms present. The relevant equation is h(bar)w = E2 - E1, which relates energy to the emitted photons.

PREREQUISITES
  • Understanding of laser physics and population inversion
  • Familiarity with ruby laser construction and operation
  • Knowledge of energy quantization and photon emission
  • Basic skills in using equations related to energy and power calculations
NEXT STEPS
  • Calculate the number of chromium atoms in the ruby crystal
  • Learn how to apply the equation h(bar)w = E2 - E1 in practical scenarios
  • Research the concept of population inversion in laser technology
  • Explore the relationship between pulse duration and average power in lasers
USEFUL FOR

Students studying laser physics, physicists interested in laser technology, and engineers working with ruby lasers or similar optical devices.

exzacklyright
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Homework Statement


Suppose that total population inversion could be achieved in a ruby laser. If half of the electrons in E2 could then drop to E1 in 30 ns, what would be the avg power of the resulting laser pulse over this time interval? Assume that the ruby crystal is a cylinder 5.00cm long and 1.19cm in diameter and that on Al in every 1700 has been replaced by a Cr. Density of Al2O3 = 3.7g/cm^3. E2-E1=1.786eV


Homework Equations



h(bar)w = E2-E1

The Attempt at a Solution



I have no idea really. That eqn above is all my book gives. Somehow it's creating a situation where more electrons are in states of energy E2 than in state of energy E1.
 
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Read this, to understand how a ruby laser works.

http://people.seas.harvard.edu/~jones/ap216/lectures/ls_2/ls2_u5/ls2_unit_5.html

In principle, you need the number of Chromium atoms in the ruby crystal to find the number of photons emitted in 30 ns.

ehild
 

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