Laurent series / residual theorem

Click For Summary
SUMMARY

The discussion focuses on solving a complex analysis problem involving the Laurent series and the residue theorem. The key approach involves converting the function cos(1/z) into its complex exponential form, expressed as cos(1/z) = 0.5 (e^(i/z) + e^(-i/z)). Participants emphasize the importance of utilizing the exponential Taylor series for manipulation, although some find the process cumbersome. The consensus suggests that familiarity with the Maclaurin series for cosine may simplify the solution process.

PREREQUISITES
  • Understanding of complex analysis concepts, specifically Laurent series
  • Familiarity with the residue theorem in complex functions
  • Knowledge of Taylor and Maclaurin series expansions
  • Ability to manipulate complex exponential functions
NEXT STEPS
  • Study the derivation and application of the Laurent series in complex analysis
  • Learn the principles of the residue theorem and its applications in contour integration
  • Explore the Taylor series and Maclaurin series for various functions
  • Practice converting trigonometric functions to their exponential forms for complex analysis problems
USEFUL FOR

Students and professionals in mathematics, particularly those studying complex analysis, as well as educators looking for effective methods to teach the concepts of Laurent series and residue theorem.

ex3e
Messages
1
Reaction score
0

Homework Statement



http://img243.imageshack.us/img243/4339/69855059.jpg

Homework Equations


i've heard that the solution requires the use of the exponential taylor series:
http://img31.imageshack.us/img31/6163/37267605.jpg

The Attempt at a Solution



i know that the first step is to convert cos(1/z) into it's complex number form which is:
cos(1/z) = 0.5 (e^(i/z) + e^(-i/z))
I've tried manipulating 1/z and z^5 into the exp.taylor series but it gets messy (might be doing it wrong). any ideas would be great!
 
Last edited by a moderator:
Physics news on Phys.org
I would say you don't have to convert the cosine to exponential form if you already know the Maclauren series of cosine.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K