Law of Sines Proof w/ Vector Calculus

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SUMMARY

The Law of Sines can be proven using vector calculus by applying the cross product of vectors representing the sides of a triangle. Specifically, the relationship sin(A)/a = sin(B)/b = sin(C)/c is established through the areas of parallelograms formed by these vectors. By defining the vectors a, b, and c and calculating their cross products, the areas can be equated, leading to the conclusion that absin(C) = bcsin(A) = casin(B), thus deriving the Law of Sines definitively.

PREREQUISITES
  • Understanding of vector calculus, specifically cross products
  • Familiarity with the Law of Sines and its geometric interpretation
  • Basic knowledge of triangle properties and trigonometric functions
  • Ability to visualize and manipulate geometric figures in a coordinate system
NEXT STEPS
  • Study vector cross product properties in detail
  • Explore geometric interpretations of trigonometric identities
  • Learn about the application of vector methods in proving other trigonometric laws
  • Investigate the relationship between area and sine functions in triangles
USEFUL FOR

Students of mathematics, particularly those studying geometry and trigonometry, as well as educators looking for effective methods to teach the Law of Sines using vector calculus.

jimmythegent
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Hey guys, it's my first post here so please don't chew my head off if I do something forbidden, hahah.

Homework Statement



Prove the Law of Sines using Vector Methods.


Homework Equations



sin(A)/a = sin(B)/b = sin(C)/c

The Attempt at a Solution



Since axb=sin(C), I decided to try getting the cross product and then trying to match it to the equation. I gave each of the points coordinates and I decided to come here for help when the problem became gigantic and hardly manageable. I've spent a couple of hours on this and I'm not getting anywhere.

If you've got any suggestions for a simpler solution or even just a nudge in the right direction, I'd be very grateful.
 
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Here's a hint:
Start by drawing a triangle with vectors, a, b, c.
Can you apply the cross-product with any pair of these vectors?
 
Yay, got it! Thanks!

I said
axb = area of parallelogram
bxc = area of parallelogram
cxa = area of parallelogram

so axb = bxc = cxa
then absin(C) = bcsin(A) = casin(B)

then crossed stuff out and got the law of sines.
 

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