Laws of motion and a projectile thrown from an accelerating elevator car

Click For Summary
SUMMARY

The discussion centers on the physics of a projectile thrown from an accelerating elevator. The ball has a vertical velocity of 4 m/s and a horizontal velocity of 3 m/s relative to the elevator, with an effective gravitational acceleration (g(eff)) of 8 m/s². Participants debate the correct approach to calculate the projectile's range, which is stated to be 5 m, while one user calculates it as 3 m. The confusion arises from the interpretation of the ball's motion relative to the elevator and the application of pseudo forces in a non-inertial frame.

PREREQUISITES
  • Understanding of projectile motion and kinematics
  • Knowledge of inertial and non-inertial reference frames
  • Familiarity with the concept of pseudo forces
  • Basic principles of acceleration and velocity in physics
NEXT STEPS
  • Study the principles of projectile motion in non-inertial frames
  • Learn about the application of pseudo forces in accelerating systems
  • Explore the effects of varying gravitational acceleration on projectile trajectories
  • Investigate the differences between relative and absolute motion in physics
USEFUL FOR

Physics students, educators, and anyone interested in understanding the complexities of motion in non-inertial reference frames, particularly in relation to projectile dynamics.

Prabs3257
Messages
65
Reaction score
4
Homework Statement
An elevator car starts descending with constant acceleration 2 m/s2 2 seconds after the start a ball is thrown horizontally with 3 m/s with respect to elevator from point P then the magnitude of displacement of the ball with respect to the point P after 1 second is
Relevant Equations
Projectile eqns
At the moment of throwing the ball the ball will have a vertical vel of 4 and horizontal of 3 wrt to elevator so as seen from inside the elevator the ball will behave like a projectile where g(eff) = 8 and with time period 1 sec hence range will be the displacement which should be 3 m but ans given is 5 m please tell me where i am wrong
 

Attachments

  • 15647727317118951486849757094766.jpg
    15647727317118951486849757094766.jpg
    43.5 KB · Views: 383
Physics news on Phys.org
I suggest you use an inertial reference frame where both the elevator and ball are moving.
 
PeroK said:
I suggest you use an inertial reference frame where both the elevator and ball are moving.
But wouldn't it be easier to solve it from inside the elevator and use pseudo force am i doing the projectile path correctly
 
Prabs3257 said:
But wouldn't it be easier to solve it from inside the elevator and use pseudo force am i doing the projectile path correctly

What does "horizontal" mean in this problem?
 
i guess it means that if seen from inside the elevator it seems as if the ball is thrown horizontally
 
Prabs3257 said:
i guess it means that if seen from inside the elevator it seems as if the ball is thrown horizontally
But, as the elevator and ball have different vertical accelerations that's not possible.
 
PeroK said:
But, as the elevator and ball have different vertical accelerations that's not possible.
but if we solve it from the elevator frame we can give that elevator's accel to the ball as pseudo force
 
Prabs3257 said:
but if we solve it from the elevator frame we can give that elevator's accel to the ball as pseudo force

Okay, so how did you get an answer of 3m?
 
so if we solve from the elevators frame ie make the elevator stationary the ball got a vertical vel of 4 and horizontal of 3 and by applying psudo force the net accel downward became 8 and time period came out to be 1 hence the displacement must be the range but my ans is not matching can you please tell me what i did wrong
 
  • #10
Prabs3257 said:
make the elevator stationary the ball got a vertical vel of 4
It says the ball is thrown horizontally relative to the elevator.
But it's not quite clear to me whether P is fixed in space or fixed to the elevator. You'd think it was fixed in space, but then I don't get any of the given answers.
 
  • #11
haruspex said:
It says the ball is thrown horizontally relative to the elevator.
But it's not quite clear to me whether P is fixed in space or fixed to the elevator. You'd think it was fixed in space, but then I don't get any of the given answers.

Working backwards, I guessed they meant horizontal in the (moving, inertial) frame of the elevator at the time the ball was projected.

Prabs3257 said:
so if we solve from the elevators frame ie make the elevator stationary the ball got a vertical vel of 4 and horizontal of 3 and by applying psudo force the net accel downward became 8 and time period came out to be 1 hence the displacement must be the range but my ans is not matching can you please tell me what i did wrong

There shouldn't be an initial vertical velocity of ##4m/s##. That would be a horizontal trajectory relative to the ground; not the elevator.
 
  • #12
haruspex said:
It says the ball is thrown horizontally relative to the elevator.
But it's not quite clear to me whether P is fixed in space or fixed to the elevator. You'd think it was fixed in space, but then I don't get any of the given answers.
i got my ans by considering that p is in the elevator
 
  • #13
PeroK said:
Working backwards, I guessed they meant horizontal in the (moving, inertial) frame of the elevator at the time the ball was projected.
Yes, that's what I wrote. My uncertainty concerns P.
 
  • #14
Prabs3257 said:
i got my ans by considering that p is in the elevator
Ok, so do that, but take the ball as being thrown horizontally relative to the instantaneous motion of the elevator.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 22 ·
Replies
22
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K