Laws of motion/static friction problem

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SUMMARY

The discussion focuses on a physics problem involving two astronauts pushing a box on an inclined ramp on the Moon. Astronaut A pushes parallel to the incline, while Astronaut B pushes horizontally. The problem requires calculating the forces exerted by both astronauts given the mass of the box (2.00 kg), the incline angle (25.0°), and static friction coefficients (0.160 and 0.380). The calculations reveal that the force required by Astronaut A is less than that required by Astronaut B, especially as the coefficient of static friction increases.

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  • Understanding of Newton's laws of motion
  • Knowledge of static friction and its coefficient
  • Ability to resolve forces into components
  • Familiarity with gravitational effects on inclined planes
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Students studying physics, educators teaching mechanics, and anyone interested in understanding forces on inclined surfaces and static friction dynamics.

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Homework Statement



Two astronauts are unloading scientific equipment from the spaceship that has just landed on the Moon surface. To prevent a box from sliding down an inclined ramp, astronaut A pushes on the box in the direction parallel to the incline, just hard enough to hold the box stationary. In an identical situation astronaut B pushes on the box horizontally. Regard as known the mass m of the box, the coefficient of static friction s between box and incline, and the inclination angle . (a) Determine the force A has to exert. (b) Determine the force B has to exert. (c) If m = 2.00 kg, = 25.0°, and s = 0.160, who has the easier job? (d) What if s = 0.380? Whose job is easier? The acceleration of gravity on the Moon is 1.625 m/s2.

Homework Equations



fstatic= coefficient of friction * normal force

The Attempt at a Solution


For A, the applied force is on the x plane so the forces in play are the applied force, the static friction force, and the x component of the normal force/mg. Both the static friction force and applied force are working against gravitational force to keep the box in place and there is no movement, so mg*sin theta = applied force + static friction force so the applied force= mg*sin theta - (coefficient of friction)(gravitational constant)??
I don't know how to tackle B though, since the applied force is neither parallel nor perpendicular to the incline.
 
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In the first case what is the frictional force?
The applied force is in the upward direction along the inclined plane. What is the direction of the frictional force and mgsinθ?
In the case of B, resolve the force into components. One along the inclined plane and the other normal to the inclined plane. Then identify the directions of mgsinθ, frictional force and the component of applied force.
 

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