LC circuit Oscillatiing current

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lpau001
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Homework Statement



An LC circuit is shown in the figure below. the 33 pF capacitor is initially charged by the 6V battery when S is at position a. Then S is thrown to position b so that the capacitor is shorted across the 15 mH Inductor.


Homework Equations



w= 1/sqrt(LC)

XL = wL

xC = 1/(wC)


The Attempt at a Solution



I didn't know where to start really, so I tried googling the problem and eventually I found that apparently

Z= |XL - XC|

But when I try to do these, my XL and XC are equal to each other, so I get 0. is this correct??
 
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ahh yea, that would make things a little difficult. Sorry.

What is the maximum value for the oscillating current assuming no resistance in the circuit?
 
lpau001 said:
ahh yea, that would make things a little difficult. Sorry.

What is the maximum value for the oscillating current assuming no resistance in the circuit?

And then there was light!

Look at it in terms of energy storage. When the capacitor is initially fully charged, it's holding onto all the available energy in a "static" state as electrical potential. When the charge on the capacitor is (briefly) zero, all the energy will be stored in the inductor's field with the maximum current running through it. Tie together the current and the energy.