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Lead is compressed reversibly with T const, find dS
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[QUOTE="Kara386, post: 5477572, member: 586556"] [h2]Homework Statement [/h2] Lead is compressed reversibly and with temperature kept constant at 300K, and from pressure of 1bar to 1000 bar. Assuming the change in volume is small, what is the [URL='https://www.physicsforums.com/insights/grandpa-chets-entropy-recipe/']change in entropy[/URL] S? Use the Maxwell relation derived from Gibbs free energy function. V = ##10^{-3}m^3##. [h2]Homework Equations[/h2] ##(\frac{\partial{V}}{\partial{T}})_p = -(\frac{\partial{S}}{\partial{p}})_T## Maxwell Relation ##\kappa = \frac{1}{V}(\frac{\partial{V}}{\partial{T}})_p = 8\times 10^{-5}K^{-1}## ##\beta = -\frac{1}{V}(\frac{\partial{V}}{\partial{p}})_T = 2.2\times 10^{-6}bar^{-1}## Where the T is meant to be a subscript denoting T constant for that derivative, but I can't make it look much like a subscript. [B] 3. The Attempt at a Solution [/B] From the Maxwell Relation, ##\kappa V = -(\frac{\partial{S}}{\partial{p}})_T## And since the process is isothermal and I know dP, I'm wondering whether I can't just rearrange so that ## \kappa V \partial p = \partial S## But that seems like wrong maths in terms of how you're allowed to treat derivatives. I suppose I'm essentially asking if that manipulation is allowed, and if not, I've tried using cyclic relationships, the central equation and other Maxwell relations but I can't seem to get anywhere. So what would I do instead?! Thanks for any help! [/QUOTE]
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Lead is compressed reversibly with T const, find dS
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