Learn How to Calculate RMS and Avoid Mistakes: Root Mean Square Help

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    Mean Root Square
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SUMMARY

This discussion focuses on calculating the Root Mean Square (RMS) for both discrete and continuous functions. The user calculates RMS for the discrete set {1, 2} using the formula x_{rms}=\sqrt{\frac{1}{n}\sum_{i=1}^{n}x_i^2} and for the continuous function f(x)=x over the interval [1, 2] using x_{rms}=\sqrt{\frac{1}{x_2-x_1}\int_{x_1}^{x_2}f^2(x)dx}. The key takeaway is that the RMS values differ due to the nature of the discrete versus continuous sets, which is a fundamental concept in mathematical analysis.

PREREQUISITES
  • Understanding of Root Mean Square (RMS) calculations
  • Familiarity with definite integrals in calculus
  • Knowledge of discrete versus continuous functions
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the properties of Root Mean Square in different contexts
  • Learn about the differences between discrete and continuous probability distributions
  • Explore advanced integral calculus techniques
  • Investigate applications of RMS in engineering and physics
USEFUL FOR

Students and professionals in mathematics, engineering, and physics who are looking to deepen their understanding of RMS calculations and their applications in various fields.

coki2000
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Hello,
For 1 and 2 I want to calculate rms then

x_{rms}=\sqrt{\frac{1}{n}\sum_{i=1}^{n}x_i^2}\Rightarrow x_{1,2}=\sqrt{\frac{1}{2}(1^2+2^2)}=\sqrt{\frac{5}{2}}

And also

x_{rms}=\sqrt{\frac{1}{x_2-x_1}\int_{x_1}^{x_2}f^2(x)dx}

For the function f(x)=x, x_1=1, x_2=2

x_{rms}=\sqrt{\frac{1}{2-1}\int_{1}^{2}x^2dx}=\sqrt{\frac{7}{3}}

Please explain to me where I do wrong.
Thanks
 
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You do nothing wrong
Are you expecting to get the same value?
Well you won't because the discrete set {1,2} is different from the continuous set {x | 1<x<2}, therefore you shouldn't get the same value
 
elibj123 said:
You do nothing wrong
Are you expecting to get the same value?
Well you won't because the discrete set {1,2} is different from the continuous set {x | 1<x<2}, therefore you shouldn't get the same value
Alright how I write this integral form?Thanks.
 

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