Learn the Basics of Anti-Derivatives: A Comprehensive Guide

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SUMMARY

This discussion focuses on the concept of anti-derivatives, specifically addressing the integration of the function (5s + 3)^2. The user attempts to solve the integral using substitution, letting u = 5s + 3, which leads to the expression \(\frac{1}{5}\int u^2~du\). The conversation highlights the importance of correctly applying integration techniques and recognizing the difference between indefinite and infinite integrals. The user seeks clarification on completing the anti-derivative process from this point.

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  • Understanding of basic calculus concepts, particularly differentiation and integration.
  • Familiarity with substitution methods in integration.
  • Knowledge of indefinite integrals and their properties.
  • Ability to manipulate algebraic expressions involving polynomials.
NEXT STEPS
  • Practice solving indefinite integrals using substitution techniques.
  • Study the Fundamental Theorem of Calculus to understand the relationship between differentiation and integration.
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Students learning calculus, educators teaching integration techniques, and anyone seeking to improve their understanding of anti-derivatives and integration methods.

groundpilots
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Anti-Derivatives Please Help!

So I am having trouble understanding where I went wrong here, the question is highlighted, then it clearly states my answer, and the answer the book gave, my work is posted in the second image, care to help??

Homework Statement


193081_10150114570475418_508690417_6587379_3018337_o1.jpg


The Attempt at a Solution



191525_10150114570890418_508690417_6587380_7031413_o.jpg

 
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Hi groundpilots! :)

\frac{d}{ds}(a+bs)^{n+1}=(n+1)(b)(a+bs)^{n}
<===>
(a+bs)^{n+1} + c =\int(n+1)(b)(a+bs)^{n} ds

With this can u tell me how u do the antiderivatives ?

If u notice b=5 and n=2 ...
 


so I tried to do the antiderivative using the formulas you gave and I still can't seem to get it...ughhhhh
here's what I tried, still not right =(

iug.jpg
 


\int (5s + 3)^2~ds

Let u = 5s + 3, then du = 5ds

Using this substitution, the integral above becomes:
\frac{1}{5}\int (5s + 3)^2~5ds = \frac{1}{5}\int u^2~du

Can you take it from here?

BTW, this is an indefinite integral, not an infinite integral.
 

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