Is There a Meaning Behind Leibniz's Derivative Notation?

Jacobim
Messages
28
Reaction score
0
is there an algebraic meaning to expressing the derivative of a function

as (d^2)y/(dx)^2 in the liebniz way
 
Physics news on Phys.org
\frac{d^{2}y}{dx^{2}}=\frac{d}{dx}(\frac{dy}{dx})

I think that's what you're asking?
 
yes, I see that now. Does the d^2 mean something? or just signifiy second derivative, i can see how the dx squared would be like acceleration is seconds^-2
 
If you multiple the d out on top you get d2y and if you multiply the bottom you get dx2
 
but the d squared is not an exponent, its a derivative...are they the same?
 
They are certainly not the same; don't think of them as exponents or fractions at all it is very misleading. It is just notation to relay the fact that you have acted the operator \frac{\mathrm{d} }{\mathrm{d} x} on f at x\in \mathbb{R} twice.
 
Back
Top