Length of Wavelength in closed aircolumn

[BarCode]

Homework Statement

An 80-cm long air column, closed at one end, contains sounding waves. How long is the wavelength that corresponds to: the first overtune

Homework Equations

v = f(lambda)

The Attempt at a Solution

no clue about what to do.

 

[Kurdt]

In a pipe with one closed end, the first harmonic (fundamental frequency) has a wavelength that is equal to 4 times the length of the pipe. This is because the closed end acts as as a node and the open end as an anti-node. What will the wavelength of the first overtone then be?

 

[Galileo's Ghost]

For a closed air column, the most simple standing wave that can occur is one with a nodal position at the closed end and an antinodal position at the open end...or 1/4 of a complete wavelength would correspond to the length of the column. Thus lambda = 4L.
There is a correction factor for the diameter of the pipe, but since you did not include that information, I will assume that the small correction factor is being ignored here.


Edit to Add...Kurdt beat me to it!