- #1
hamza2095
- 28
- 1
Homework Statement
The resonant length of a closed air column at the first resonance is 0.375m, what is the wavelength when at 4th reasonance
Homework Equations
The Attempt at a Solution
1/4λ=0.375m
λ=1.5m
1.5m/7 = 0.214m
This was a question on a test, the way I got the answer was knowing v/f=λ and i knew that 7/4 of the wave fits in the 4th reasonance and 1/4 in the first, meaning the frequency is 7x more. I assumed the the velocity was 1.5m/s and the frequency was 1hz so 1.5ms/1hz = 1.5m, after that i mutliplied the 1 hz by 7 to get the answer. Is there an easier way to go about this?, I had trouble with it because the neither the speed of sound or frequency was given.TSny said:As third poster, I second your fourth resonance answer.
That's the key.hamza2095 said:i knew that 7/4 of the wave fits in the 4th reasonance
The length of a closed air column refers to the distance between the closed end and the open end of the air column, where sound waves can travel and resonate.
The length of a closed air column directly affects the pitch of a sound. A shorter air column will produce a higher pitch, while a longer air column will produce a lower pitch.
The length of a closed air column and the wavelength of a sound wave are inversely proportional. This means that as the length of the air column increases, the wavelength of the sound wave decreases, and vice versa.
The length of a closed air column has no direct impact on the speed of sound. However, it can indirectly affect the speed of sound by changing the frequency and wavelength of the sound wave.
The length of a closed air column can be changed by physically altering the length of the column, such as by adjusting the length of a wind instrument or changing the size of a closed space. It can also be changed by changing the temperature or pressure of the air column.