An object is at distance s from a thin glass lens of focal length f. The lens is surrounded
by air. The image is at distance s' from the lens. Draw a graph of s' versus s. Explain
physically why the graph varies as it does.
I think I am supposed to use the thin lens equation of 1/s+1/s'=1/f.
The Attempt at a Solution
For a fixed focal length, an increase in s causes the linearly proportional decrease in s'? As an object is moved farther away from the lens, the image also moves farther away.
I don't understand how this equation is independent from the case of a convex or concave lens.
Thanks for any help!