Lever system - brake (counting of forces)

[Bublifuk]

Hello.
I tried to solve this question:

So F₁D₁=F₂D₂. Thus:
60N/ 0,06m x 0,2 m= f/0,02m x 0,04m
=100 Newton applied to the piston, but this doesn't fit to the answers offered.
What did I wrong?:(

 

[nasu]

Why are you dividing the 60 N force by 6 cm?

 

[Bublifuk]

Because it applies some force on the area, isn't it?

It's so easy, that I just need to divide 60N by 0,2M?

 

[nasu]

Because it applies some force on the area, isn't it?

It's so easy, that I just need to divide 60N by 0,2M?

I think you are mixing the lever rule with the hydraulic press (Pascal principle).
The question is about forces. You don't need pressures. And dividing by 6 cm will not give pressure anyway (it's piston's diameter not its area).
Are there more questions related to the same diagram?

 

[Bublifuk]

No, only this one.
Have you managed to solve it?

 

[nasu]

Use the equation for the lever or just equilibrium of torques around the pivot.