Levi-Civita Identity Proof Help (εijk εijl = 2δkl)

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 3K views
John Delaney
Messages
3
Reaction score
1
Homework Statement
Prove εijk εijl = 2δkl
Relevant Equations
εijk εilm = δjl δkm - δjm δkl
I assumed that this would be a straightforward proof, as I could just make the substitution l=j and m=l, but upon doing this, I end up with:

δjj δkl - δjl δkj

= δkl - δlk

Clearly I did not take the right approach in this proof and have no clue as to how to proceed.
 
Physics news on Phys.org
Well you are right that you can do it just by making a 'substitution'. However, bear in mind that summation convention is in use here. You have to sum over the indices that are repeating. With that, you should be able to get the right result.
 
Antarres said:
Well you are right that you can do it just by making a 'substitution'. However, bear in mind that summation convention is in use here. You have to sum over the indices that are repeating. With that, you should be able to get the right result.

Thank you for the reminder, completely forgot that δjj = 3 rather than 1.