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Light as a particle/ compton effect, conservation of energy and momentum

  1. Dec 5, 2012 #1
    1. The problem statement, all variables and given/known data

    1. A photon with an initial energy of 33eV collides with an electron. If the speed of the electron after the collision is 4.56*10^5m/s the final energy of the photon is? [32.4eV]

    2. Photons that compose a monochromatic beam of light each have a momentum of 1.50*10^-28 kgm/s. The period of this light [1.47*10^-14s]

    3. an xray photon of wavelength .010nm strikes a helium nucleus (alpha particle) and bounces straight back. If the helium nucleus was originally at rest, calculate its velocity after interacting with the x-ray [2*104m/s]

    4. A photon moving in an easterly direction with an energy of 6.21 *10^-15 J collides with an electron and scatters at an angle of 30 W of S. What is the velocity of the electron after the collision? [3.74 *10^7m/s [28 N of E]]

    5. Calculate the frequency of an electron that has a speed of 9.2*10^5m/s [1.16*10^15hz]
    2. Relevant equations

    e=hf
    E=1/2mv^2
    conservation of momentum/energy
    p=mv or h/lambda

    3. The attempt at a solution

    1.Energy of photon before = energy of electron after + energy of photon after.
    energy of photon after = energy of photon before - energy of electron after

    Ea = 33eV - (1/2 (9.11*10^-31) (4.56*10^5)^2)

    i get 33eV seeing as how the energy of the electron is 9.47*10^-20 very small i can see why, what did i do wrong? this is my attempt maybe i did the whole thing wrong?


    2. I have no idea how to relate momentum of a photon (p=h/lambda) to time, no velocity some help here?

    3. Is this conservation of energy? I tried hf=1/2mv^2 , but it didnt make sense and didnt work when you solve for v.

    4. Am i not missing something in this question for conservation of energy i believe i dont have enough information, or at least i cant get it.

    5. lambda = h/mv
    lambda =(6.63*10^-34)/(9.11*10^-31)(9.2*10^5) =7.910 *10^-10 m

    f = c/lambda = 3.79*10^17

    i dont where else to get frequncy.. cant use Ek=hf
     
    Last edited: Dec 6, 2012
  2. jcsd
  3. Dec 6, 2012 #2
    solved 1 and 2.
     
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