1. The problem statement, all variables and given/known data Two narrow slits are 0.12 mm apart. Light of wavelength 550 nm illuminates the slits, causing an interference pattern on a screen 1.0 m away. Light from each slit travels to the m=1 maximum on the right side of the central maximum. Part A - How much farther did the light from the left slit travel than the light from the right slit? Express your answer using two significant figures. 2. Relevant equations r=dsin(theta) (theta)_{m} = m*(lambda/d) y=L*tan(theta) y_{m} = (m*lambda*L)/d 3. The attempt at a solution I don't understand how to do these problems... theta_{m} = (m*lambda*)/d theta_{m} = (1*(5.5*10^-7m)/(1m) theta_{m} = 5.5*10^-7 path length difference = dsin(theta) so... r = d*sin(theta) r = 1m *sin(5.5*10^-7) r = 9.599^-9m r = 9.6nm That doesn't appear to be the correct answer(Unless MasteringPhysics is wrong). Sadly, I don't know if I did the right steps or used the correct equations. Any help is appreciated. 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution
Hi Foxhound101, Remember that this is really: [tex] \sin\theta=\frac{m\lambda}{d} [/tex] The approximation you are using ([itex]\theta=\frac{m\lambda}{d}[/itex]) is fine since the angle is small enough, but remember that this approximation is true if the angle is measured in radians. So the angle you found is [itex]5.5\times 10^{-7}\mbox{ rad}[/itex]. This number was calculated with the angle measure set to degrees, not radians.