Light refracted through Prism question

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To determine the maximum angle "alpha" for which no light exits the prism at face AC, one must consider the principles of total internal reflection and the critical angle. Given the refractive index of the glass prism is 1.67, the critical angle can be calculated using Snell's law. When light travels from a denser medium (glass) to a less dense medium (air), it will not refract out if the angle of incidence exceeds the critical angle. This analysis leads to the conclusion that the largest angle "alpha" must be less than the critical angle to ensure total internal reflection occurs at face AC.
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Light refracted through Prism question~~

Homework Statement



Here is the problem:


Light is incident along the normal to face AB of a glass prism of refractive index 1.67, as shown in the figure.

Find, "alpha_max" the largest value of the angle "alpha" such that no light is refracted out of the prism at face AC if the prism is immersed in air.

-The diagram is a simple one of a right triangle representing the prism, the topmost corner is labeled A, and B and C are the base corners. Therefore, side AC is the hypotenuse, and Angle "alpha" is located at corner C. Hope all this makes sense! Let me know if it doesn't.

Any help is appreciated!
 
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Look up "total internal reflection" and "critical angle"
 

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