Light travelling through several polarizers

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Homework Help Overview

The problem involves three polarizers arranged in a line, with one polarizer rotating over time. The original poster seeks to determine the intensity of light transmitted through the system as a function of time, referencing a specific textbook problem and related equations.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply Malus's Law to calculate the intensity of light after passing through the polarizers, expressing concern over a discrepancy in their result compared to the expected answer. Other participants question the implications of using only one polarizer and whether the original poster's calculations are correct.

Discussion Status

The discussion is ongoing, with participants exploring the calculations and assumptions made by the original poster. There is a request for clarification regarding the attachment, indicating that additional context may be needed to fully understand the problem setup.

Contextual Notes

The original poster references a specific textbook problem and expresses uncertainty about a potential typo in the expected solution. There is also mention of an attachment that may provide further details about the polarizer arrangement.

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Homework Statement


This is problem 71, chapter 38 in Physics for Scientists and Engineers 8th edition by Serway/Jewett.

Three polarizers are situated in a straight line with one spinning in the middle with θ=ωt.
Find the intensity of light coming out the other side as a function of time.
The attachment is the diagram of the system.

Homework Equations


Manus's Law: I = Imax cos2 θ. Where θ is the angle between the transmission axis for the two polarizers.

The Attempt at a Solution


Through the first two polarizers we have:
I= Imax cos2 θ = Imax cos2 ωt
which becomes
I= Imax/2 (1+ cos(2ωt))

Then the light from the second polarizer is:
I= Imax/2 (1+ cos(2ωt)) cos2 (90-ωt)= Imax/2 (1+ cos(2ωt)) sin2 (ωt)

and this turns into:
Imax/4 (1+ cos(2ωt))(1- cos(2ωt))
Imax/4 (1- cos2 (2ωt))
Imax/4 (1-(1+cos(4ωt)/2))
And for the answer we have:
Imax/8 (1- cos(4ωt))

The problem is the book expects the solution to be:
Imax/16 (1- cos(4ωt))

So I am off by a factor of 2. Can anyone see my problem or could it be a typo?
 

Attachments

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Please provide the attachment.
 
Must not have clicked upload the first time.
 
What would the intensity be with only one polariser?
 
*face to palm* Thanks Haruspex
 

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