- #1
tffnyyy
- 2
- 0
here is the problem. i got 0.5 from the fact that thickness = (m)(lambda)/(2nf)
other equation for thickness is thickness = (m+1/2)(lambda)/(2nf)
Light wave incident on and passing through a thin soap film
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SUMMARY
The discussion centers on calculating the thickness of a thin soap film using the equations thickness = (m)(lambda)/(2nf) and thickness = (m+1/2)(lambda)/(2nf). The participants emphasize the importance of providing the correct values for wavelength and refractive index, as well as ensuring the answer is presented to two significant digits. Additionally, the units of thickness (d) are clarified to be multiples of lambda, highlighting the need for precision in calculations.
PREREQUISITES- Understanding of wave optics principles
- Familiarity with the concept of refractive index
- Knowledge of significant figures in scientific calculations
- Basic grasp of wavelength and its role in interference patterns
- Research the principles of thin film interference
- Learn about the calculation of refractive indices for various materials
- Study the significance of significant figures in scientific reporting
- Explore the relationship between wavelength and film thickness in optical applications
Students and professionals in physics, particularly those studying optics, as well as anyone involved in experiments or applications related to thin films and light interference.
here is the problem. i got 0.5 from the fact that thickness = (m)(lambda)/(2nf)
other equation for thickness is thickness = (m+1/2)(lambda)/(2nf)
- #2
andrevdh
- 2,126
- 116
It seems that you have value for the wavelength and or refractive index? Note also that they want the answer to two significant digits where you only supplied one. What are the units of d? Is it multiples of lambda? I notice that there is a lambda to the right of the answer?
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