Lightyears and the surface area of a planet.

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SUMMARY

A light year is defined as the distance light travels in one year, approximately 9.45e12 kilometers. To calculate the surface area of a sphere with a radius of 1300 km, the formula used is SA = 4πR², resulting in approximately 6.76e6π km². To convert this surface area into lightyears², the correct approach involves dividing by 8.94e25 km²/lightyears², yielding a final result of approximately 2.38e-19 lightyears². The conversion process must account for the correct dimensional analysis to ensure accurate unit cancellation.

PREREQUISITES
  • Understanding of the concept of a light year as a unit of distance
  • Familiarity with the formula for the surface area of a sphere (SA = 4πR²)
  • Knowledge of dimensional analysis and unit conversion
  • Basic mathematical skills for squaring numbers and performing division
NEXT STEPS
  • Research dimensional analysis techniques for unit conversions
  • Learn more about the properties and calculations involving spheres
  • Explore the implications of using astronomical units in scientific calculations
  • Study the speed of light and its significance in astrophysics
USEFUL FOR

Students in physics or astronomy, educators teaching unit conversions, and anyone interested in understanding the relationship between distance and surface area in astronomical contexts.

niyati
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A light year is the unit of distance that light, with a speed of 2.99792e8 m/s, travels in one year. What is the surface area of a planet whose radius is 1300 km? Answer in units of lightyears^2.

I am wondering if my method is correct.

SA of a sphere is 4[pi]R^2. With R = 1300, the surface area is 6.76e6[pi] km^2. Since they want this number in terms of light years, I need to first, well, convert the ratio into years. With dimension analysis (not the internet), I found that there was 31536000 seconds in one year. Setting up a proportion, that's about 9.45e15 meters in one year, or 9.45e12 km in one year. I squared that number (this is the part I am most unsure about) and then divided 6.76e6[pi] by about 8.94e25 km^2, to get 2.38e-19. But I don't think that's right, because the dimensions actually cancel, then.

>_<

Help?
 
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You should divide 6.76e6[pi] km^2 by 8.94e25 km^2/lighyears^2. The units will be okay.
 
Thank you!

I forgot about km^2 being overlightyears^2.

:D
 

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