Exploring the Limit of (1+f(x))^g(x) as x Approaches Infinity

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In summary, the conversation discusses two different limits of (1+f(x))^g(x) as x approaches positive infinity. The first limit is equal to e^(f(x)*g(x)), which was proven in class. The second limit is equal to e^(-0.5*C) if lim g(x)*f(x)^2 = C, but its validity is questioned as it was given without proof. Examples are given where both limits do not coincide, indicating a potential error in the formulas. It is suggested that additional conditions may be needed for the formulas to be accurate.
  • #1
jojay99
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Hi guys,

What is the limit of (1+f(x))^g(x) as x approaches positive infinity?

We were taught two limits in class:

lim (1+f(x))^g(x) = lim exp(f(x)*g(x))

and

lim (1+f(x))^g(x) = exp(-0.5*C) if lim g(x)*f(x)^2=C

We were given a proof of the first one in class so I'm sure it's correct. However, I'm not too sure about the second one (it was given without proof). Does the second one seem right to you guys?

I'm going through a few problems where both limits do not coincide with each other. Therefore, something must be wrong since limits (from one side) must be unique.
 
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  • #2
f(x)=1/x, g(x)=x, the second formula would give C=0 and therefore a limit of 1, which is wrong.
f(x)=1/sqrt(x), g(x)=x, the second formula would give C=1 and therefore a limit of -exp(1/2), which is wrong (the limit does not exist at all)
Maybe the second formula has some additional requirements?
 
  • #3
The first one seems wrong too, without additional conditions. For example if f(x) = 1, g(x) = 1 then the first formula gives 2 = e, which is wrong. I would guess that you need the additional condition that lim f(x) = 0.
 
  • #4
This is just nonsense.
You haven't grasped critical information about the functions' behaviours.
you have.
(1+f)^g=e^(ln(1+f)*g)
and unless you have specific knowledge of how f and g behaves, nothing of what you write is meaningful.
 

FAQ: Exploring the Limit of (1+f(x))^g(x) as x Approaches Infinity

What is the limit of (1+f(x))^g(x) as x approaches infinity?

The limit of (1+f(x))^g(x) as x approaches infinity is equal to 1. This is because as x becomes infinitely large, the impact of the function f(x) becomes negligible and the function approaches (1)^g(x), which is equal to 1.

What is the limit of (1+f(x))^g(x) as x approaches 0?

The limit of (1+f(x))^g(x) as x approaches 0 is equal to 1. This is because as x becomes infinitely small, the impact of the function f(x) becomes negligible and the function approaches (1)^g(x), which is equal to 1.

What is the limit of (1+f(x))^g(x) as g approaches infinity?

The limit of (1+f(x))^g(x) as g approaches infinity is equal to infinity. This is because as g becomes infinitely large, the function approaches (1)^g(x), which grows infinitely as g increases.

What is the limit of (1+f(x))^g(x) as g approaches 0?

The limit of (1+f(x))^g(x) as g approaches 0 is equal to 1. This is because as g becomes infinitely small, the function approaches (1)^g(x), which is equal to 1.

What is the limit of (1+f(x))^g(x) as both x and g approach infinity?

The limit of (1+f(x))^g(x) as both x and g approach infinity is indeterminate. This is because the behavior of the function depends on the specific values of f(x) and g(x) and cannot be determined without further information.

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