Limit of e^(-2x) * cosx as x-> ∞

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SUMMARY

The limit of e^(-2x) * cos(x) as x approaches infinity is definitively 0. While the limit of cos(x) oscillates between -1 and 1 and does not exist, the exponential decay of e^(-2x) dominates the behavior of the product. The application of the squeeze theorem confirms that the limit converges to 0, as e^(-2x) approaches 0 faster than cos(x) can oscillate.

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  • Understanding of limits in calculus
  • Familiarity with exponential functions, specifically e^(-2x)
  • Knowledge of trigonometric functions, particularly cos(x)
  • Concept of the squeeze theorem in mathematical analysis
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Problem statement: Find the limit of e^(-2x) * cosx as x-> ∞

Attempt at solution: I tried to say that the limit of e^(-2x) as x-> ∞ is 0, and the limit of cosx doesn't exist since it oscillates between -1 and 1 therefore the overall answer is that it doesn't exist. I was wrong however and the right answer was 0. Could someone please help?
 
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limit of cos(x) doesn't exist but can you put bounds on its absolute value?

whats the limit of e^(-2x) times the upper bound?
 
Try applying the squeeze theorem.
 

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