Limit of x2cosh(1/x) as x approaches 0
The Attempt at a Solution
I did some algebra,made into the form infinity over infinity and used hopital's rule. I got limit x2e^(1/x).
Then I again made into the form infinity over infinity(by making it 1/x2).
Then used hopital's rule again and ended up getting limit of e^(1/x) as x approaches 0.
Can I assume that it is infinity? But when I draw the graph of e^(1/x),using my graphic calculator, it shows the right and left limits are different and therefore the limit does not exist.
Sorry for not showing my steps as I cannot find the limit and other symbols on latex.Thank you for reading!