Limit of logarithm of square roots function

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SUMMARY

The limit of the logarithm of square roots function is proven to hold under the condition that \(\sqrt{s} >> m\). The limit simplifies to \(\log\left(\frac{s}{m^2}\right)\) by manipulating the expression inside the logarithm. Key techniques include factoring out \(\sqrt{s}\) from both the numerator and denominator and applying Taylor expansion for \(\sqrt{1-x}\) where \(x = \frac{4m^2}{s} \rightarrow 0\). This approach effectively resolves the limit as required.

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Homework Statement


I need to prove that the following limit holds when

\sqrt{s}>>m

\log\left(\frac{\sqrt{s}+\sqrt{s-4m^2}}{\sqrt{s}-\sqrt{s-4m^2}}\right) \rightarrow \log\left(\frac{s}{m^2}\right)

The Attempt at a Solution


I've tried several manipulations using logarithms properties but had no success.

Thanks
 
Last edited:
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You don't need to bother with the logarithm, just focus on the stuff inside. I'll give you a starting hint; you should provide the rest of your workings after that if you can't get it and want further help. To start, I would pull the factor of \sqrt{s} out from the top and bottom of the fraction inside the logarithm. Find the limiting form of the fraction in your desired limit.
 
Hello Mute, thanks for the help. I've managed to do it, after Taylor expansion of \sqrt{1-x}, where in my limit:

x=\frac{4m^2}{s}\rightarrow 0.

As I'm under some time pressure to finish this, very bigg, home exam I'm already not thinking so clearly..

Thanks again
 

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