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Find the limit as n -> infinity

So I separated the fraction into [tex] (1/3)(2/3)^n [/tex]

Then limit = 1/3 [tex] lim_(n->infinity) (2/3)^n. [/tex]

So, my question is, how do you find the limit [tex] (2/3)^n. [/tex] Is analysis of functions simply enough, i.e. looking at how fast they increase?