Limit problem simplify the root

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StrSpeed
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Homework Statement


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I feel like I'm missing some theorem which is preventing me from finalizing this problem! It's been driving me nuts I feel like I'm missing something super basic!

Ultimately they've given the solution, g/8, so I know this is how I should try to get the equation to look algebraically. But, no matter how I manipulate it I can't get it to reduce.

I feel like this has to do with √x2 = |x| Which then depending on your value of x will give x, or -x. However, I can't simplify the root into a way which will let me make this jump.
Printed physics problem 44 on relativity: Einstein's theory reduces to Newtonian mechanics as c tends to infinity; h(c) = c√(c²/g² + 1/4 − c²/g) and prove lim h(c) = g/8 as c → ∞.


Homework Equations


https://www.desmos.com/calculator/hf8poewlvb

The Attempt at a Solution


https://www.desmos.com/calculator/hf8poewlvb
(link to all my reductions)
 
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Try multiplying numerator and denominator by$$
c\sqrt{\left(\frac{c^2}{g^2}+\frac 1 4\right)}+\frac{c^2}{g}$$
 
The conjugate! How could I forget that.. Thank you! Now I have:

PS. g is not squared I wrote it down wrong.
Handwritten limit expression: 1/4 times the limit as c approaches infinity of c^2 divided by the square root of (c^2/(9a) + 1/4) plus c^2/(9a).


Let me see what more I can do.
 
Alternatively: You can take a common factor out of the expression under the square root to obtain [tex] h(c) = A\sqrt{1 + x} - \frac{c^2}{g}[/tex] where [itex]x < 1[/itex] for sufficiently large [itex]c[/itex]. Hence you may expand the root as a binomial series, [tex] (1 + x)^{\alpha} = 1 + \alpha x + \frac{\alpha(\alpha - 1)}{2!}x^2 + \dots[/tex]
 
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Thanks for both of your help! Still working on it, sadly.. I pulled out a C so I'm left with:

https://www.physicsforums.com/file:///C:/Users/Steven/Downloads/CodeCogsEqn.gif
Handwritten-style math: (1/4) times the limit as x approaches 0 of c divided by the square root of (c^2/g^2 + 1/4 + c/g).


Im not entirely sure what I could pull out of the root.
 
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StrSpeed said:
Thanks for both of your help! Still working on it, sadly.. I pulled out a C so I'm left with:

https://www.physicsforums.com/file:///C:/Users/Steven/Downloads/CodeCogsEqn.gif
Handwritten-style limit expression: 1/4 times Limit as x approaches 0 of c divided by the square root of (c^2/g^2 + 1/4) plus c/g.


Im not entirely sure what I could pull out of the root.
Factor out the c you'll have 1/4 * (lim c ->0 1/(sqrt(1/g^2 + 1/4c) + 1/g) and don't forget that 1/4c goes to 0 whenever c -> 0, good luck
 
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StrSpeed said:
The conjugate! How could I forget that.. Thank you! Now I have:

PS. g is not squared I wrote it down wrong.
Handwritten expression: one quarter times the limit as c approaches infinity of c squared over the square root of (c squared over g squared plus one quarter), plus c squared over g squared.


Let me see what more I can do.
That's good.

##\displaystyle \ \frac14\lim_{c\to\infty}\left(\frac{c^2}{\displaystyle c\sqrt{\left(\frac{c^2}{g^2}+\frac 1 4\right)}+\frac{c^2}{g}}\right)\ ##

One way to deal with rational expressions where some factor →∞ : divide the numerator and denominator by the highest power of that factor.

Divide by c2 in the numerator & denominator.
 
I got it! You guys rock thank you so much! Once I got down to that last x Term I realized that a constant/infinity = 0!

Here is my work through!
Handwritten calculus work evaluating lim as c approaches infinity of h(c) = c√(c²/g² + 1/4) - c²/g, multiplied by its conjugate, with the final result lim as c approaches infinity of 9/8 circled.
 
You should drop the limit sign from the second last row.
 
StrSpeed said:
I got it! You guys rock thank you so much! Once I got down to that last x Term I realized that a constant/infinity = 0!

Here is my work through!
Handwritten derivation: the limit as x tends to infinity of 1/4 times 1/(1/2 times the square root of (2/(9x^2) + 1/(4x)) + 1/9), then an equals sign, a boxed rewrite with 1/4 limit of 1/(square root of (1/(9x^2) + 1/(4x) + 1/9)), times 9/9.
At the point highlighted above, simply take the limit and simplify.