# Limit with trigonometric functions

1. Nov 23, 2009

### Jules18

1. The problem statement, all variables and given/known data

True or false?

lim Tanx/(1-Cosx) = lim Sec2x/Sinx = Infinity

(limits are as x approaches $$\pi$$ from the left)

3. The attempt at a solution

I tried just plugging $$\pi$$ into x in the first limit, and I ended up getting 0/2, which exists but is just 0. So I said false. Am I simplifying it too much? because what I did seems to make sense but it looks like that's not what they wanted me to do.

Last edited: Nov 23, 2009
2. Nov 23, 2009

### mlarson9000

Re: limit

Isn't it just 0/2=0?

3. Nov 24, 2009

### Staff: Mentor

Re: limit

The original limit was neither of the indeterminate forms [0/0] or [infinity/infinity], so L'Hopital's Rule doesn't apply here. Your first approach was correct.