rondo09
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[tex]{{\lim_{\substack{x\rightarrow\pi}} {\left( \frac {x}{x-\pi}{\int_{\pi}^{x} }\frac{sin t}{t}} dt\right)}[/tex]
The discussion focuses on evaluating the limit of the complex function as x approaches π, specifically the expression \lim_{\substack{x\rightarrow\pi}} {\left( \frac {x}{x-\pi}{\int_{\pi}^{x} }\frac{sin t}{t}} dt\right)}. The primary challenge arises from the indeterminate form "0/0" when applying the limit. Participants recommend using L'Hôpital's rule to resolve this, leading to the conclusion that the limit evaluates to the integrand at π, which is sin(π)/π = 0.
Students and professionals in mathematics, particularly those studying calculus, as well as educators seeking to enhance their understanding of limit evaluation techniques.
The expression is simply the derivative of the integral, i.e. the integrand at π, which is sin(π)/π = 0.HallsofIvy said:First, of course, that "x" outside the integral goes to [itex]\pi[/itex]. The only problem is
[tex]\lim_{x\to\pi}\frac{\int_\pi^x \frac{sin(t)}{t} dt}{x- \pi}[/tex]
which gives the "0/0" indeterminate form.
Use L'Hopital's rule to find that limit.